To understand the concept of p value is very important. To teach the the distribution of common statistic( \(\chi^2\) for chisq.test() , t for Student’s t-test , F for F-test) and concept of the p-value, plot.htest() function can be used.

Package Installation

You can install this package form the github. Currently, package webr is under construction and consists of only one function - plot.htest().

#install.packages("devtools")
devtools::install_github("cardiomoon/webr")

Coverage of plot.htest()

The plot.htest() function is a S3 method for class “htest”. Currently, this function covers Welch Two Sample t-test, Pearson’s Chi-squared test, Two Sample t-test, One Sample t-test, Paired t-test and F test to compare two variances.

For Chi-squared Test

You can show the distribution of chi-squre statistic and p-value.

 require(moonBook)
 require(webr)
 
 # chi-squared test
 x=chisq.test(table(acs$sex,acs$DM))
 x

    Pearson's Chi-squared test with Yates' continuity correction

data:  table(acs$sex, acs$DM)
X-squared = 3.1296, df = 1, p-value = 0.07688
 plot(x)

For one sample t-test

You can show the distribution of t-statistic and p-value in one sample t-test.

t.test(acs$age,mu=63)

    One Sample t-test

data:  acs$age
t = 0.77978, df = 856, p-value = 0.4357
alternative hypothesis: true mean is not equal to 63
95 percent confidence interval:
 62.52736 64.09574
sample estimates:
mean of x 
 63.31155 
plot(t.test(acs$age,mu=63))

Student t-test to compare means for two independent samples

Before performing a t-test, you have to compare two variances.

F test to compare two variances

x=var.test(age~DM,data=acs)
x

    F test to compare two variances

data:  age by DM
F = 1.2383, num df = 552, denom df = 303, p-value = 0.0376
alternative hypothesis: true ratio of variances is not equal to 1
95 percent confidence interval:
 1.012416 1.505776
sample estimates:
ratio of variances 
          1.238288 
plot(x)

Use for Two Sample t-test for independence samples

Based on the result of var.test(), you can perform t.test with default option(var.equal=FALSE).

x=t.test(age~DM,data=acs)
x

    Welch Two Sample t-test

data:  age by DM
t = 0.58982, df = 682.36, p-value = 0.5555
alternative hypothesis: true difference in means is not equal to 0
95 percent confidence interval:
 -1.112568  2.068014
sample estimates:
 mean in group No mean in group Yes 
         63.48101          63.00329 
plot(x)

Student t-test using pooled variance

To compare means of body-mass index between male and female patients, perform F test first.

var.test(BMI~sex,data=acs)

    F test to compare two variances

data:  BMI by sex
F = 1.2078, num df = 254, denom df = 508, p-value = 0.07756
alternative hypothesis: true ratio of variances is not equal to 1
95 percent confidence interval:
 0.9794315 1.5008098
sample estimates:
ratio of variances 
          1.207759 
plot(var.test(BMI~sex,data=acs))

Based on the result of F test, you can perform t-test using pooled variance.

x=t.test(BMI~sex,data=acs,var.equal=TRUE)
x

    Two Sample t-test

data:  BMI by sex
t = -0.50823, df = 762, p-value = 0.6114
alternative hypothesis: true difference in means is not equal to 0
95 percent confidence interval:
 -0.6348532  0.3737344
sample estimates:
mean in group Female   mean in group Male 
            24.19492             24.32548 
plot(x)

Paired t-test

You can show the distribution of t-statistic and p-value in paired t-test.

x=t.test(iris$Sepal.Width,iris$Petal.Width,paired=TRUE)
plot(x)

Options for t-test

You can change the options of t.test.

x=t.test(BMI~sex, data=acs,conf.level=0.99,alternative="greater",var.equal=TRUE)
plot(x)